![带分数的二元一次方程组怎样解 (2x+y)/4-[5(x-2y)]/3=6 [3(2x+y)]/4-(x-y)/3=4](/upload/images/2023/0621/17b4a02b.jpg)
(2x+y)/4-[5(x-2y)]/3=6 [3(2x+y)]/4-(x-y)/3=4(2x+y)/4-[5(x-2y)]/首悔3=46 [3(2x+y)]/4-(x-y)/3=4俩个方程分别化简：-14x+43y=4852x+29y=24俩式连列纯者即可求解者裤正
带分数的二元一次方程组怎样解 (2x+y)/4-[5(x-2y)]/3=6 [3(2x+y)]/4-(x-y)/3=4
Simone
发布于 2023-07-06 14:42:17
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